2[k-(4k+20)+12]=2(k+8)

Solution for 2[k-(4k+20)+12]=2(k+8) equation:

Simplifying
2[k + -1(4k + 20) + 12] = 2(k + 8)

Reorder the terms:
2[k + -1(20 + 4k) + 12] = 2(k + 8)
2[k + (20 * -1 + 4k * -1) + 12] = 2(k + 8)
2[k + (-20 + -4k) + 12] = 2(k + 8)

Reorder the terms:
2[-20 + 12 + k + -4k] = 2(k + 8)

Combine like terms: -20 + 12 = -8
2[-8 + k + -4k] = 2(k + 8)

Combine like terms: k + -4k = -3k
2[-8 + -3k] = 2(k + 8)
[-8 * 2 + -3k * 2] = 2(k + 8)
[-16 + -6k] = 2(k + 8)

Reorder the terms:
-16 + -6k = 2(8 + k)
-16 + -6k = (8 * 2 + k * 2)
-16 + -6k = (16 + 2k)

Solving
-16 + -6k = 16 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-16 + -6k + -2k = 16 + 2k + -2k

Combine like terms: -6k + -2k = -8k
-16 + -8k = 16 + 2k + -2k

Combine like terms: 2k + -2k = 0
-16 + -8k = 16 + 0
-16 + -8k = 16

Add '16' to each side of the equation.
-16 + 16 + -8k = 16 + 16

Combine like terms: -16 + 16 = 0
0 + -8k = 16 + 16
-8k = 16 + 16

Combine like terms: 16 + 16 = 32
-8k = 32

Divide each side by '-8'.
k = -4

Simplifying
k = -4